Bài 132: trang 55 sgk Toán 6 tập 2
Tìm x, biết:
a) \(2{2 \over 3}.x + 8{2 \over 3} = 3{1 \over 3}\)
b) \(3{2 \over 7}.x - {1 \over 8} = 2{3 \over 4}\)
Bài Làm:
a) \(2{2 \over 3}.x + 8{2 \over 3} = 3{1 \over 3}\)
\(\frac{8}{3}x+\frac{26}{3}=\frac{10}{3}\)
\(8x+26=10\)
\(8x=10-26\)
\(8x=-16\)
\(x=-16 \div 8\)
\(x=-2\)
b) \(3{2 \over 7}.x - {1 \over 8} = 2{3 \over 4}\)
\(\frac{23}{7}x-\frac{1}{8}=\frac{11}{4}\)
\(\frac{23}{7}x=\frac{22}{8}+\frac{1}{8}\)
\(\frac{23}{7}x=\frac{23}{8}\)
\(x=\frac{23}{8} \div \frac{23}{7}\)
\(x=\frac{23}{8} .\frac{7}{23}\)
\(x=\frac{7}{8}\)
