Câu 2: Trang 16 - sgk Toán lớp 5
Tìm x:
x +$\frac{1}{4}=\frac{5}{8}$
x -$\frac{3}{5}=\frac{1}{10}$
$x \times \frac{2}{7}=\frac{6}{11}$
x :$\frac{3}{2}=\frac{1}{4}$
Bài Làm:
a) x +$\frac{1}{4}=\frac{5}{8}$
x =$\frac{5}{8}$ - $\frac{1}{4}$
x =$\frac{3}{8}$
b) x -$\frac{3}{5}=\frac{1}{10}$
x =$\frac{1}{10}$ + $\frac{3}{5}$
x = $\frac{7}{10}$
c) $x \times \frac{2}{7}=\frac{6}{11}$
x =$\frac{6}{11}$ : $\frac{2}{7}$
x = $\frac{21}{11}$
d) x :$\frac{3}{2}=\frac{1}{4}$
x = $\frac{1}{4} \times \frac{3}{2}$
x = $\frac{3}{8}$
