Bài 1: Trang 13 VBT toán 5 tập 1
< < = |
$5\frac{1}{7}$ ... $2\frac{6}{7}$ $3\frac{2}{7}$ ... $3\frac{5}{7}$
$8\frac{6}{10}$ ... $8\frac{3}{5}$ $9\frac{1}{2}$ ... $5\frac{1}{2}$
Bài Làm:
$5\frac{1}{7}$ > $2\frac{6}{7}$ $3\frac{2}{7}$ < $3\frac{5}{7}$
$8\frac{6}{10}$ = $8\frac{3}{5}$ $9\frac{1}{2}$ > $5\frac{1}{2}$